(3t/t^2-16)+(6/t+4)=1/t-4

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Solution for (3t/t^2-16)+(6/t+4)=1/t-4 equation: 



(3t/t^2-16)+(6/t+4)=1/t-4

We move all terms to the left:

(3t/t^2-16)+(6/t+4)-(1/t-4)=0



Domain of the equation: t^2-16)!=0

t∈R





Domain of the equation: t+4)!=0

t∈R





Domain of the equation: t-4)!=0

t∈R



We get rid of parentheses

3t/t^2+6/t-1/t-16+4+4=0

We calculate fractions

We do not support etpression: t^3

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